3.147 \(\int \frac{(b \sqrt [3]{x}+a x)^{3/2}}{x^5} \, dx\)

Optimal. Leaf size=438 \[ -\frac{44 a^{21/4} \sqrt [6]{x} \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{\frac{a x^{2/3}+b}{\left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{a x+b \sqrt [3]{x}}}-\frac{88 a^{11/2} \sqrt [3]{x} \left (a x^{2/3}+b\right )}{1105 b^4 \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{a x+b \sqrt [3]{x}}}+\frac{88 a^3 \sqrt{a x+b \sqrt [3]{x}}}{4641 b^2 x^{5/3}}+\frac{88 a^{21/4} \sqrt [6]{x} \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{\frac{a x^{2/3}+b}{\left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{a x+b \sqrt [3]{x}}}+\frac{88 a^5 \sqrt{a x+b \sqrt [3]{x}}}{1105 b^4 \sqrt [3]{x}}-\frac{88 a^4 \sqrt{a x+b \sqrt [3]{x}}}{3315 b^3 x}-\frac{24 a^2 \sqrt{a x+b \sqrt [3]{x}}}{1547 b x^{7/3}}-\frac{12 a \sqrt{a x+b \sqrt [3]{x}}}{119 x^3}-\frac{2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{7 x^4} \]

[Out]

(-88*a^(11/2)*(b + a*x^(2/3))*x^(1/3))/(1105*b^4*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[b*x^(1/3) + a*x]) - (12*a*Sq
rt[b*x^(1/3) + a*x])/(119*x^3) - (24*a^2*Sqrt[b*x^(1/3) + a*x])/(1547*b*x^(7/3)) + (88*a^3*Sqrt[b*x^(1/3) + a*
x])/(4641*b^2*x^(5/3)) - (88*a^4*Sqrt[b*x^(1/3) + a*x])/(3315*b^3*x) + (88*a^5*Sqrt[b*x^(1/3) + a*x])/(1105*b^
4*x^(1/3)) - (2*(b*x^(1/3) + a*x)^(3/2))/(7*x^4) + (88*a^(21/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[(b + a*x^(2/3
))/(Sqrt[b] + Sqrt[a]*x^(1/3))^2]*x^(1/6)*EllipticE[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(1105*b^(15/4)*
Sqrt[b*x^(1/3) + a*x]) - (44*a^(21/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[(b + a*x^(2/3))/(Sqrt[b] + Sqrt[a]*x^(1
/3))^2]*x^(1/6)*EllipticF[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(1105*b^(15/4)*Sqrt[b*x^(1/3) + a*x])

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Rubi [A]  time = 0.640416, antiderivative size = 438, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.421, Rules used = {2018, 2020, 2025, 2032, 329, 305, 220, 1196} \[ -\frac{88 a^{11/2} \sqrt [3]{x} \left (a x^{2/3}+b\right )}{1105 b^4 \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{a x+b \sqrt [3]{x}}}+\frac{88 a^3 \sqrt{a x+b \sqrt [3]{x}}}{4641 b^2 x^{5/3}}-\frac{44 a^{21/4} \sqrt [6]{x} \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{\frac{a x^{2/3}+b}{\left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{a x+b \sqrt [3]{x}}}+\frac{88 a^{21/4} \sqrt [6]{x} \left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right ) \sqrt{\frac{a x^{2/3}+b}{\left (\sqrt{a} \sqrt [3]{x}+\sqrt{b}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{a x+b \sqrt [3]{x}}}+\frac{88 a^5 \sqrt{a x+b \sqrt [3]{x}}}{1105 b^4 \sqrt [3]{x}}-\frac{88 a^4 \sqrt{a x+b \sqrt [3]{x}}}{3315 b^3 x}-\frac{24 a^2 \sqrt{a x+b \sqrt [3]{x}}}{1547 b x^{7/3}}-\frac{12 a \sqrt{a x+b \sqrt [3]{x}}}{119 x^3}-\frac{2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{7 x^4} \]

Antiderivative was successfully verified.

[In]

Int[(b*x^(1/3) + a*x)^(3/2)/x^5,x]

[Out]

(-88*a^(11/2)*(b + a*x^(2/3))*x^(1/3))/(1105*b^4*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[b*x^(1/3) + a*x]) - (12*a*Sq
rt[b*x^(1/3) + a*x])/(119*x^3) - (24*a^2*Sqrt[b*x^(1/3) + a*x])/(1547*b*x^(7/3)) + (88*a^3*Sqrt[b*x^(1/3) + a*
x])/(4641*b^2*x^(5/3)) - (88*a^4*Sqrt[b*x^(1/3) + a*x])/(3315*b^3*x) + (88*a^5*Sqrt[b*x^(1/3) + a*x])/(1105*b^
4*x^(1/3)) - (2*(b*x^(1/3) + a*x)^(3/2))/(7*x^4) + (88*a^(21/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[(b + a*x^(2/3
))/(Sqrt[b] + Sqrt[a]*x^(1/3))^2]*x^(1/6)*EllipticE[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(1105*b^(15/4)*
Sqrt[b*x^(1/3) + a*x]) - (44*a^(21/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[(b + a*x^(2/3))/(Sqrt[b] + Sqrt[a]*x^(1
/3))^2]*x^(1/6)*EllipticF[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(1105*b^(15/4)*Sqrt[b*x^(1/3) + a*x])

Rule 2018

Int[(x_)^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)
/n] - 1)*(a*x^Simplify[j/n] + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[
n, j] && IntegerQ[Simplify[j/n]] && IntegerQ[Simplify[(m + 1)/n]] && NeQ[n^2, 1]

Rule 2020

Int[((c_.)*(x_))^(m_)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a*x^j + b*
x^n)^p)/(c*(m + j*p + 1)), x] - Dist[(b*p*(n - j))/(c^n*(m + j*p + 1)), Int[(c*x)^(m + n)*(a*x^j + b*x^n)^(p -
1), x], x] /; FreeQ[{a, b, c}, x] &&  !IntegerQ[p] && LtQ[0, j, n] && (IntegersQ[j, n] || GtQ[c, 0]) && GtQ[p
, 0] && LtQ[m + j*p + 1, 0]

Rule 2025

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[(c^(j - 1)*(c*x)^(m - j +
1)*(a*x^j + b*x^n)^(p + 1))/(a*(m + j*p + 1)), x] - Dist[(b*(m + n*p + n - j + 1))/(a*c^(n - j)*(m + j*p + 1)
), Int[(c*x)^(m + n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, p}, x] &&  !IntegerQ[p] && LtQ[0, j,
n] && (IntegersQ[j, n] || GtQ[c, 0]) && LtQ[m + j*p + 1, 0]

Rule 2032

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Dist[(c^IntPart[m]*(c*x)^FracP
art[m]*(a*x^j + b*x^n)^FracPart[p])/(x^(FracPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p]), Int[x^(m
+ j*p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[n, j] && PosQ[n
- j]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 305

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 2]}, Dist[1/q, Int[1/Sqrt[a + b*x^4], x],
x] - Dist[1/q, Int[(1 - q*x^2)/Sqrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 220

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[((1 + q^2*x^2)*Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]*EllipticF[2*ArcTan[q*x], 1/2])/(2*q*Sqrt[a + b*x^4]), x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 1196

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[c/a, 4]}, -Simp[(d*x*Sqrt[a + c
*x^4])/(a*(1 + q^2*x^2)), x] + Simp[(d*(1 + q^2*x^2)*Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]*EllipticE[2*ArcTan[
q*x], 1/2])/(q*Sqrt[a + c*x^4]), x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e}, x] && PosQ[c/a]

Rubi steps

\begin{align*} \int \frac{\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^5} \, dx &=3 \operatorname{Subst}\left (\int \frac{\left (b x+a x^3\right )^{3/2}}{x^{13}} \, dx,x,\sqrt [3]{x}\right )\\ &=-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}+\frac{1}{7} (6 a) \operatorname{Subst}\left (\int \frac{\sqrt{b x+a x^3}}{x^{10}} \, dx,x,\sqrt [3]{x}\right )\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}+\frac{1}{119} \left (12 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{x^7 \sqrt{b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (132 a^3\right ) \operatorname{Subst}\left (\int \frac{1}{x^5 \sqrt{b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{1547 b}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}+\frac{\left (44 a^4\right ) \operatorname{Subst}\left (\int \frac{1}{x^3 \sqrt{b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{663 b^2}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (44 a^5\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{1105 b^3}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}+\frac{88 a^5 \sqrt{b \sqrt [3]{x}+a x}}{1105 b^4 \sqrt [3]{x}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (44 a^6\right ) \operatorname{Subst}\left (\int \frac{x}{\sqrt{b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{1105 b^4}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}+\frac{88 a^5 \sqrt{b \sqrt [3]{x}+a x}}{1105 b^4 \sqrt [3]{x}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (44 a^6 \sqrt{b+a x^{2/3}} \sqrt [6]{x}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{x}}{\sqrt{b+a x^2}} \, dx,x,\sqrt [3]{x}\right )}{1105 b^4 \sqrt{b \sqrt [3]{x}+a x}}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}+\frac{88 a^5 \sqrt{b \sqrt [3]{x}+a x}}{1105 b^4 \sqrt [3]{x}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (88 a^6 \sqrt{b+a x^{2/3}} \sqrt [6]{x}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{1105 b^4 \sqrt{b \sqrt [3]{x}+a x}}\\ &=-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}+\frac{88 a^5 \sqrt{b \sqrt [3]{x}+a x}}{1105 b^4 \sqrt [3]{x}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}-\frac{\left (88 a^{11/2} \sqrt{b+a x^{2/3}} \sqrt [6]{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{1105 b^{7/2} \sqrt{b \sqrt [3]{x}+a x}}+\frac{\left (88 a^{11/2} \sqrt{b+a x^{2/3}} \sqrt [6]{x}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{a} x^2}{\sqrt{b}}}{\sqrt{b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{1105 b^{7/2} \sqrt{b \sqrt [3]{x}+a x}}\\ &=-\frac{88 a^{11/2} \left (b+a x^{2/3}\right ) \sqrt [3]{x}}{1105 b^4 \left (\sqrt{b}+\sqrt{a} \sqrt [3]{x}\right ) \sqrt{b \sqrt [3]{x}+a x}}-\frac{12 a \sqrt{b \sqrt [3]{x}+a x}}{119 x^3}-\frac{24 a^2 \sqrt{b \sqrt [3]{x}+a x}}{1547 b x^{7/3}}+\frac{88 a^3 \sqrt{b \sqrt [3]{x}+a x}}{4641 b^2 x^{5/3}}-\frac{88 a^4 \sqrt{b \sqrt [3]{x}+a x}}{3315 b^3 x}+\frac{88 a^5 \sqrt{b \sqrt [3]{x}+a x}}{1105 b^4 \sqrt [3]{x}}-\frac{2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{7 x^4}+\frac{88 a^{21/4} \left (\sqrt{b}+\sqrt{a} \sqrt [3]{x}\right ) \sqrt{\frac{b+a x^{2/3}}{\left (\sqrt{b}+\sqrt{a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{b \sqrt [3]{x}+a x}}-\frac{44 a^{21/4} \left (\sqrt{b}+\sqrt{a} \sqrt [3]{x}\right ) \sqrt{\frac{b+a x^{2/3}}{\left (\sqrt{b}+\sqrt{a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{1105 b^{15/4} \sqrt{b \sqrt [3]{x}+a x}}\\ \end{align*}

Mathematica [C]  time = 0.0548633, size = 62, normalized size = 0.14 \[ -\frac{2 b \sqrt{a x+b \sqrt [3]{x}} \, _2F_1\left (-\frac{21}{4},-\frac{3}{2};-\frac{17}{4};-\frac{a x^{2/3}}{b}\right )}{7 x^{11/3} \sqrt{\frac{a x^{2/3}}{b}+1}} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x^(1/3) + a*x)^(3/2)/x^5,x]

[Out]

(-2*b*Sqrt[b*x^(1/3) + a*x]*Hypergeometric2F1[-21/4, -3/2, -17/4, -((a*x^(2/3))/b)])/(7*Sqrt[1 + (a*x^(2/3))/b
]*x^(11/3))

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Maple [A]  time = 0.026, size = 411, normalized size = 0.9 \begin{align*}{\frac{2}{23205\,{b}^{4}{x}^{7}} \left ( -924\,{a}^{5}b\sqrt{{\frac{a\sqrt [3]{x}+\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{-2\,{\frac{a\sqrt [3]{x}-\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{-{\frac{a\sqrt [3]{x}}{\sqrt{-ab}}}}{x}^{{\frac{20}{3}}}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{\it EllipticE} \left ( \sqrt{{\frac{a\sqrt [3]{x}+\sqrt{-ab}}{\sqrt{-ab}}}},1/2\,\sqrt{2} \right ) +462\,{a}^{5}b\sqrt{{\frac{a\sqrt [3]{x}+\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{-2\,{\frac{a\sqrt [3]{x}-\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{-{\frac{a\sqrt [3]{x}}{\sqrt{-ab}}}}{x}^{{\frac{20}{3}}}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{\it EllipticF} \left ( \sqrt{{\frac{a\sqrt [3]{x}+\sqrt{-ab}}{\sqrt{-ab}}}},1/2\,\sqrt{2} \right ) +924\,{x}^{{\frac{22}{3}}}\sqrt{b\sqrt [3]{x}+ax}{a}^{6}+924\,{x}^{{\frac{20}{3}}}\sqrt{b\sqrt [3]{x}+ax}{a}^{5}b-88\,{x}^{6}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{a}^{4}{b}^{2}-308\,{x}^{{\frac{20}{3}}}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{a}^{5}b-4665\,{x}^{14/3}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{a}^{2}{b}^{4}+40\,{x}^{16/3}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{a}^{3}{b}^{3}-7800\,{x}^{4}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }a{b}^{5}-3315\,{x}^{10/3}\sqrt{\sqrt [3]{x} \left ( b+a{x}^{2/3} \right ) }{b}^{6} \right ) \left ( b+a{x}^{{\frac{2}{3}}} \right ) ^{-1}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^(1/3)+a*x)^(3/2)/x^5,x)

[Out]

2/23205*(-924*a^5*b*((a*x^(1/3)+(-a*b)^(1/2))/(-a*b)^(1/2))^(1/2)*(-2*(a*x^(1/3)-(-a*b)^(1/2))/(-a*b)^(1/2))^(
1/2)*(-x^(1/3)*a/(-a*b)^(1/2))^(1/2)*x^(20/3)*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*EllipticE(((a*x^(1/3)+(-a*b)^(1/2)
)/(-a*b)^(1/2))^(1/2),1/2*2^(1/2))+462*a^5*b*((a*x^(1/3)+(-a*b)^(1/2))/(-a*b)^(1/2))^(1/2)*(-2*(a*x^(1/3)-(-a*
b)^(1/2))/(-a*b)^(1/2))^(1/2)*(-x^(1/3)*a/(-a*b)^(1/2))^(1/2)*x^(20/3)*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*EllipticF
(((a*x^(1/3)+(-a*b)^(1/2))/(-a*b)^(1/2))^(1/2),1/2*2^(1/2))+924*x^(22/3)*(b*x^(1/3)+a*x)^(1/2)*a^6+924*x^(20/3
)*(b*x^(1/3)+a*x)^(1/2)*a^5*b-88*x^6*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*a^4*b^2-308*x^(20/3)*(x^(1/3)*(b+a*x^(2/3))
)^(1/2)*a^5*b-4665*x^(14/3)*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*a^2*b^4+40*x^(16/3)*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*a^
3*b^3-7800*x^4*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*a*b^5-3315*x^(10/3)*(x^(1/3)*(b+a*x^(2/3)))^(1/2)*b^6)/b^4/x^7/(b
+a*x^(2/3))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + b x^{\frac{1}{3}}\right )}^{\frac{3}{2}}}{x^{5}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^(1/3)+a*x)^(3/2)/x^5,x, algorithm="maxima")

[Out]

integrate((a*x + b*x^(1/3))^(3/2)/x^5, x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (a x + b x^{\frac{1}{3}}\right )}^{\frac{3}{2}}}{x^{5}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^(1/3)+a*x)^(3/2)/x^5,x, algorithm="fricas")

[Out]

integral((a*x + b*x^(1/3))^(3/2)/x^5, x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**(1/3)+a*x)**(3/2)/x**5,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + b x^{\frac{1}{3}}\right )}^{\frac{3}{2}}}{x^{5}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^(1/3)+a*x)^(3/2)/x^5,x, algorithm="giac")

[Out]

integrate((a*x + b*x^(1/3))^(3/2)/x^5, x)